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Sagot :
Given
[tex]y+3=\frac{1}{3}(x-5)[/tex]To graph the above line.
Explanation:
It is given that,
[tex]y+3=\frac{1}{3}(x-5)[/tex]That implies,
[tex]\begin{gathered} 3(y+3)=x-5 \\ 3y+9=x-5 \\ x-3y-5-9=0 \\ x-3y-14=0 \end{gathered}[/tex]Then,
Hence, the graph of the above line is plotted as,
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