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Graph the line.y + 3 = 1/3 * (x - 5)

Sagot :

Given

[tex]y+3=\frac{1}{3}(x-5)[/tex]

To graph the above line.

Explanation:

It is given that,

[tex]y+3=\frac{1}{3}(x-5)[/tex]

That implies,

[tex]\begin{gathered} 3(y+3)=x-5 \\ 3y+9=x-5 \\ x-3y-5-9=0 \\ x-3y-14=0 \end{gathered}[/tex]

Then,

Hence, the graph of the above line is plotted as,

View image EllisenE781629
View image EllisenE781629