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Each row in the table below shows one possible set of angle measurements for this drawing.

Sagot :

First let;s fill the second row

It is given that

[tex]\begin{gathered} \angle DFE=36 \\ \angle AFE=180-36=144 \end{gathered}[/tex][tex]\angle AFB=36\text{ (VERTICALLY O}\P OSITE\text{ TO }\angle DFE)[/tex][tex]\angle BFC=90-36=54[/tex]

Now let us fill the third row :-

It is given that

[tex]\angle AFE=140[/tex]

So

[tex]\angle DFE=180-140=40\text{ (LINEAR PAIR)}[/tex][tex]\angle AFB=\angle DFE=40\text{ (vertically opposite angles)}[/tex][tex]\angle BFC=90-40=50\text{ }[/tex]

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