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What is the area of a rectangle with side lengths of 5/12 foot and 2/3 foot?A: 7/36 square footB: 10/36 square footC: 15/24 square footD: 7/15 square foot

Sagot :

The Area of a Rectangle

A rectangle of width W and length L has an area calculated as:

[tex]A=W\cdot L[/tex]

We are given the side lengths W = 2/3 and L = 5/12. The order of the sides is not important because the area is a product and it's a commutative operation.

Calculating:

[tex]A=\frac{2}{3}ft\cdot\frac{5}{12}ft[/tex]

Multiplying numerators and denominators separately:

[tex]A=\frac{10}{36}ft^2[/tex]

This fraction can be simplified but if we do, we won't be able to find the correct choice, thus:

Area = B: 10/36 square foot

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