Answered

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A rectangle has an area of 6x2 - 12x. If the length is 2x, what is the width?

Sagot :

ANSWER

[tex]W=3x-6[/tex]

EXPLANATION

We have that the area of the rectangle is:

[tex]A=6x^2-12x[/tex]

and the length is:

[tex]2x[/tex]

The area of a rectangle is given as:

[tex]A=L\cdot W[/tex]

where L = length; W = width

This means that to find the width, we can divide the area by the length.

That is:

[tex]W=\frac{A}{L}[/tex]

This implies that:

[tex]\begin{gathered} W=\frac{6x^2-12x}{2x} \\ \Rightarrow W=\frac{6x^2}{2x}-\frac{12x}{2x} \\ W=3x-6 \end{gathered}[/tex]

That is the width of the rectangle.

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