Given the condition 90 degrees counterclockwise, we use rule below:
When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative.
Hence, To get J';
[tex]\begin{gathered} A(x,y)=A^{\prime}(-y,x) \\ J(x,y)=J^{\prime}(-y,x) \\ J(1,-3)=J^{\prime}(-(-3),1) \\ J^{\prime}=(3,1) \end{gathered}[/tex]To get K':
[tex]\begin{gathered} K(x,y)=K^{\prime}^{}(-y,x) \\ K(5,0)=K^{\prime}(-0,5) \\ K^{\prime}=(0,5) \end{gathered}[/tex]To get L':
[tex]\begin{gathered} L(x,y)=L^{\prime}^{}(-y,x) \\ L(8,-4)=L^{\prime}(-(-4),8) \\ L^{\prime}=(4,8) \end{gathered}[/tex]To get M':
[tex]\begin{gathered} M(x,y)=M^{\prime}^{}(-y,x) \\ M(4,-7)=M^{\prime}(-(-7),4) \\ M^{\prime}=(7,4) \end{gathered}[/tex]Therefore, the values of J',K',L' and M' are respectively given below;
[tex]\begin{gathered} J^{\prime}=(3,1) \\ K^{\prime}=(0,5) \\ L^{\prime}=(4,8) \\ M^{\prime}=(7,4) \end{gathered}[/tex]