Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
[tex]6.023\text{ x 10}^{23}\text{ molecules are present in 1 mole of CuSO}_4\text{ i.e. 159.5 g of CuSO}_4[/tex]
So, using unitary method
[tex]3.36\text{ x 10}^{23}\text{ molecules will be there in }\frac{159.5}{6.023\text{ x 10}^{23}}\text{ x 3.36 x10}_{\placeholder{⬚}^{\placeholder{⬚}}}^{23}[/tex][tex]=\text{ 88.97 g of CuSO}_4[/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
