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Sagot :
In order to find the linear equation, use the following general equation for a line:
[tex]y-y_o=m(x-x_o)[/tex]where:
m: slope of the line = -2
(xo,yo): coordinate of a point on the line = (-8,-2)
Replace the previous values of the parameters into the general equation for a line and solve for y, as follow:
[tex]\begin{gathered} y-(-2)=-2(x-(-8)) \\ y+2=-2(x+8) \\ y+2=-2x-16 \\ y=-2x-16-2 \\ y=-2x-18 \end{gathered}[/tex]Hence, the equation of the line is y = -2x - 18
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