Answered

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Roger is 55 4/5 inches tall.Shauna is 1 1/3 inches shorter than Shauna how tall is jane

Sagot :

Let:

x = Roger height

y = Shauna height

z = Jane height

[tex]\begin{gathered} x=55\frac{4}{5}=\frac{279}{5} \\ y=x-1\frac{1}{6}=x-\frac{7}{6}=\frac{279}{5}-\frac{7}{6}=\frac{1639}{30} \\ z=y-1\frac{1}{3}=y-\frac{4}{3}=\frac{1639}{30}-\frac{4}{3}=53\frac{3}{10}in=\frac{533}{10}in=53.3in \end{gathered}[/tex]

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