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Victor drew trapezoid PQRS on a coordinate plane. The coordinates of each vertex are:

Victor Drew Trapezoid PQRS On A Coordinate Plane The Coordinates Of Each Vertex Are class=

Sagot :

Correct answer is option (D).

Given:

Coordinates of point P and S are, P (8,4) and S (8,-1).

The objective is to find the length of the side PS.

Consider the given coordinates as,

[tex]\begin{gathered} (x_1,y_1)=(8,4) \\ (x_2,y_2)=(8,-1) \end{gathered}[/tex]

The length between two coordinates can be calculated using the distance formula,

[tex]d=\sqrt[]{(x_2-x_1)^2+(x_2-x_1)^2}[/tex]

Substitute the given values in the above formula.

[tex]\begin{gathered} d=\sqrt[]{(8-8)^2+(-1-4)^2} \\ d=\sqrt[]{0^2+(-5)^2} \\ d=\sqrt[]{25} \\ d=\pm5 \end{gathered}[/tex]

Since the length cannot be negative, so +5.

Thus, the length of the side PS is, 5 units.

Hence, option (D) is the correct answer.