Answered

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At constant temperature and pressure, if 0.4 mole of a gas A occupies 220 mL and x mole of B gas occupies 120 mL, what is the number of moles of gas in the container that holds them B?

Sagot :

Given:

The number of moles in gas A is,

[tex]n_A=0.4\text{ mole}[/tex]

The volume of gas A is,

[tex]V_A=220\text{ ml}[/tex]

The volume of gas B is,

[tex]V_B=120\text{ ml}[/tex]

To find:

The number of moles of gas in the container that holds them B

Explanation:

According to the ideal gas equation, as the constant temperature and pressure are constant,

[tex]\begin{gathered} PV=nRT \\ \frac{V}{n}=\frac{RT}{P} \\ \frac{V}{n}=constant \end{gathered}[/tex]

So, we write,

[tex]\begin{gathered} \frac{V_A}{n_A}=\frac{V_B}{n_B} \\ n_B=\frac{V_Bn_A}{V_A} \\ n_B=\frac{120\times0.4}{220} \\ n_B=0.22 \end{gathered}[/tex]

Hence, the number of moles of gas in container B is 0.22.

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