Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

At constant temperature and pressure, if 0.4 mole of a gas A occupies 220 mL and x mole of B gas occupies 120 mL, what is the number of moles of gas in the container that holds them B?

Sagot :

Given:

The number of moles in gas A is,

[tex]n_A=0.4\text{ mole}[/tex]

The volume of gas A is,

[tex]V_A=220\text{ ml}[/tex]

The volume of gas B is,

[tex]V_B=120\text{ ml}[/tex]

To find:

The number of moles of gas in the container that holds them B

Explanation:

According to the ideal gas equation, as the constant temperature and pressure are constant,

[tex]\begin{gathered} PV=nRT \\ \frac{V}{n}=\frac{RT}{P} \\ \frac{V}{n}=constant \end{gathered}[/tex]

So, we write,

[tex]\begin{gathered} \frac{V_A}{n_A}=\frac{V_B}{n_B} \\ n_B=\frac{V_Bn_A}{V_A} \\ n_B=\frac{120\times0.4}{220} \\ n_B=0.22 \end{gathered}[/tex]

Hence, the number of moles of gas in container B is 0.22.

We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.