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For m>0, the expression (in the image) can be rewritten in the form 2m^a, where a is a fraction. Then a=___

For Mgt0 The Expression In The Image Can Be Rewritten In The Form 2ma Where A Is A Fraction Then A class=

Sagot :

From the question;

we need to simplify

[tex]\frac{2(\sqrt[]{m})^3}{\sqrt[4]{m}}[/tex]

In the form

[tex]2m^a[/tex]

solving

[tex]\begin{gathered} \frac{2(\sqrt[]{m})^3}{\sqrt[4]{m}} \\ =\text{ }\frac{2(m^{\frac{1}{2}})^3}{m^{\frac{1}{4}}} \\ =\text{ }\frac{2m^{3\text{ }\times\frac{1}{2}}}{m^{\frac{1}{4}}} \\ =\text{ }\frac{2m^{\frac{3}{2}}}{m^{\frac{1}{4}}} \\ \text{applying law of indices} \\ =2m^{\frac{3}{2}\text{ - }\frac{1}{4}} \\ =2m^{\frac{6\text{ - 1}}{4}} \\ =2m^{\frac{5}{4}} \end{gathered}[/tex]

comparing the result

[tex]\begin{gathered} 2m^{\frac{5}{4}}=2m^a \\ \text{implies} \\ m^{\frac{5}{4}}=m^a \end{gathered}[/tex]

Hence,

The value of a is

[tex]\frac{5}{4}[/tex]