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On Earth, a 500-gram bucket is lifted from the ground to a height of 7 meters. In order to liftit, a 5 Newton force is applied to the bucket, directed upwards. What is the magnitude of thebucket's acceleration as it is lifted?

Sagot :

Answer:

0.2 m/s²

Explanation:

The situation can be model as shown in the following diagram

Therefore, the net force on the bucket will be equal to the force of 5N less the weight of the bucket. Then:

Fnet = 5 N - mg

Replacing m by 500 gram and g by the acceleration of gravity 9.8 m/s², we get:

Fnet = 5 N - 0.5Kg(9.8 m/s²)

Fnet = 5N - 4.9N

Fnet = 0.1 N

Now, by the second law of Newton, the net force is equal to the mass time the acceleration so:

Fnet = ma

0.1N = 0.5Kg(a)

Solving for a, we get:

0.1N/ 0.5Kg = a

0.2 m/s² = a

Therefore, the magnitude of the bucket's acceleration is 0.2 m/s²

Fnet = 5 N -

View image KevontaeS348084
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