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Sagot :
Given the expression 8x+3y>15
To write it in y-intercept form you have to write the equation in terms of y: y=mx+b
To do so you have to leave y in one side of the inequation and all other terms must be in the other side of the inequation
[tex]\begin{gathered} 8x+3y>15\text{ \rightarrow{}subtract8x to both sides} \\ 8x-8x+3y>15-8x \\ 3y>15-8x\to\text{divide both sides by 3} \\ \frac{3y}{3}>\frac{15}{3}-\frac{8x}{3} \\ y>5-\frac{8}{3}x \end{gathered}[/tex]The y-intercept form i¡of the expression is y=5-8/3x
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8x+3y>15 → subtract 8x from both sides of the inequation
8x-8x+3y>15-8x
3y>15-8x → divide both sides by 3
3y/3>15/3-8x/3
y>5-8/3x
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