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Solve forx. Round to the nearest tenth of a degree, if necessary.

Solve Forx Round To The Nearest Tenth Of A Degree If Necessary class=

Sagot :

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

The details of the solution are as follows:

From the diagram, we can see that:

[tex]\begin{gathered} \sin x^0=\text{ }\frac{opposite}{\text{Hypotenuse}}=\frac{PO}{PN}=\frac{4.2}{9.\text{ 5}}=0.4421 \\ \text{Then, taking the sine inverse, we have that:} \\ x\text{ =}\sin ^{-1}(0.4421) \\ \text{x = 26.23794635} \\ x\text{ }\approx26.2^0(\text{ to the nearest tenth)} \end{gathered}[/tex]

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