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In the figure below, m∠ABD=104° , and m∠2 is 18° more than m∠1. Find m∠1.

In The Figure Below MABD104 And M2 Is 18 More Than M1 Find M1 class=

Sagot :

Given the following parameters

[tex]\begin{gathered} m\angle ABD=104^0 \\ m\angle2=18^0 \\ m\angle1\Rightarrow? \end{gathered}[/tex]

From the diagram, we can say that the <1 and <2 are adjacent.

we can say that.

[tex]m\angle1+m\angle2=104^0[/tex]

Substitute for m<2 =18 degrees in the equation above, to find m<1

[tex]\begin{gathered} m\angle1+18^0=104^0 \\ m\angle1=104^0-18^0 \\ m\angle1=86^0 \end{gathered}[/tex]

Hence, the m<1 is 86°

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