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An airplane is flying at an altitude of 6000 m over the ocean directly toward a coastline.At a certain time, the angle of depression to the coastline from the airplane is 14°. Howmuch farther (to the nearest meter) does the airplane have to fly before it is directlyabove the coastline?O 1496 mO 1451 mO 24065 mO 5822 m

Sagot :

In a diagram,

Solving for x (notice that we are dealing with a right triangle),

[tex]\begin{gathered} tan(14\degree)=\frac{6000}{x} \\ \Rightarrow x=\frac{6000}{tan(14\degree)}=1495.968...\approx1496 \end{gathered}[/tex]

Thus, the answer is 1496m, the first option.

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