Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Given the equation:
[tex]\sec ^2(x)-6\sec (x)=0[/tex]To solve this, we observe that sec(x) can not be 0. Simplifying the equation:
[tex]\begin{gathered} \sec ^2(x)=6\sec (x) \\ \frac{\sec ^2(x)}{\sec (x)}=6 \\ \sec (x)=6 \\ \frac{1}{\sec (x)}=\frac{1}{6} \\ \cos (x)=\frac{1}{6} \\ x=\cos ^{-1}(\frac{1}{6}) \end{gathered}[/tex]This is equal to (in radians), and given that the period of the cosine is 2π:
[tex]x=1.4033+2\pi n[/tex]
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
