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Sagot :
Given the two-way table, let's find the probability that a student selected at random is a junior student given that it's male.
Total number of students = 4 + 6 + 2 + 2 + 3+ 4 + 6 + 3 = 30
Number of male students = 4 + 6 + 2 + 2 = 14
Number of female students = 3 + 4 + 6 + 3 = 16
To find the probability that a randomly selected student is a junior given that the student is male, we have:
[tex]P=\frac{Number\text{ of male }juniors}{\text{Number of male students}}[/tex]Where:
Number of male junior students = 2
Number of male students = 14
Thus, we have:
[tex]P=\frac{2}{14}=\frac{1}{7}[/tex]To write the probability as a percentage, multiply by 100:
[tex]\begin{gathered} P=\frac{1}{7}\ast100 \\ \\ P=\frac{100}{7}=14.3\approx\text{ 14\%} \end{gathered}[/tex]Therefore, the probability that a randomly selected student is a junior given that it's male is 14%
A
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