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Help me please. Im struggling and trying to pass the 12th grade

Help Me Please Im Struggling And Trying To Pass The 12th Grade class=

Sagot :

From a given right triangle,

We observe that,

[tex]\begin{gathered} O\text{pposite side=6 cm} \\ \text{Adjacent side=6}\sqrt[]{3}cm \\ \text{Hypotenuous side=12cm} \end{gathered}[/tex]

Using the formula,

[tex]\begin{gathered} \sin A=\frac{opp}{hyp} \\ \sin A=\frac{6\sqrt[]{3}}{12} \\ \sin A=\frac{\sqrt[]{3}}{2} \\ A=\sin ^{-1}(\frac{\sqrt[]{3}}{2}) \\ A=60^{\circ} \end{gathered}[/tex]

Using the formula,

[tex]\begin{gathered} \sin B=\frac{opp}{hyp} \\ \sin B=\frac{6}{12} \\ \sin B=\frac{1}{2} \\ B=30^{\circ} \end{gathered}[/tex]

Hence, the answer is,

[tex]A=60^{\circ},B=30^{\circ}[/tex]

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