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Sagot :
Answer:
The solution is:
[tex]-10OR (-10,4)Explanation:Given:
[tex]\begin{gathered} 4x-3\le13\ldots\ldots\ldots....\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots.(1) \\ -x-5<5\ldots\ldots\ldots\ldots\ldots........\ldots.\ldots\ldots\ldots\ldots\text{.}(2) \end{gathered}[/tex]From (2), we have:
[tex]x>-10\ldots\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots\text{.}(3)[/tex]Using this (1)
[tex]\begin{gathered} 4x\le16 \\ \\ x\le\frac{16}{4}=4\ldots\ldots\ldots\ldots.......\ldots\ldots\ldots\ldots\ldots\ldots\ldots..(4) \end{gathered}[/tex]The solution now is:
[tex]-10
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