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12. How many Kilojoules are needed to convert 3.50 g of ice at 0 degrees Celsius to water at 80 degreeCelsius?

Sagot :

answer and explanation

this question requires us to determine the total energy required for the heating of ice to water at 80 degrees.

first we can use the specific heat equation which is

q = m x Cp x T

q - heat

m- mass

Cp - is specific heat

T- is the change in temperature

Cp of water is 4.185j/g deg Celcius

therefore

q = (3.50)(4.185)(80)

= 1171.8 J

but we also need to calculate the change from ice to water and we can use the latent heat formula

q = mL

L is the latent heat of fusion/vapourization of a substance

q = (3.50)( 334)

= 1169J

therefore the total energy needed is 1169 + 1171.8 = 2340.8 J or 2.34KJ