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Mike has only 2 red apples and 3 green apples in abowl. Without looking he chooses an apple and doesnot replace it. Then he chooses another apple. What isthe probability that both apples chosen will be red?

Sagot :

First pick: Random apple

2 out of the 5 apples are red. Therefore, the probability of choosing a red apple is:

[tex]\frac{2}{5}[/tex]

Second pick: Red apple removed

We're left with 4 apples, one of which is red.

Therefore, the probability of choosing the red apple from this bowl is:

[tex]\frac{1}{4}[/tex]

To get the probability of the two events happening right next to each other, we mulitply both probabilities:

[tex]\frac{2}{5}\cdot\frac{1}{4}=\frac{1}{10}[/tex]

Meaning that the probability that both apples chosen will be red is 1/10, or 10%

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