Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
First, we find the acceleration of the car using the following formula.
[tex]v_f=v_0+at[/tex]Where the final speed is zero (because the car stops), the initial speed is 86.55 km/h, and the time is 4.163 seconds. Let's replace these magnitudes and solve for a.
[tex]\begin{gathered} 0=86.55(\frac{km}{h})+a\cdot4.163\sec \\ -86.55(\frac{km}{h})=a\cdot4.163\sec \\ a=\frac{-86.55(\frac{km}{h})}{4.163\sec } \end{gathered}[/tex]But, we have to transform the speed from km/h to m/s.
[tex]\frac{86.55\operatorname{km}}{h}\cdot\frac{1000m}{1\operatorname{km}}\cdot\frac{1h}{3600\sec }\approx24.04(\frac{m}{s})[/tex]Then, we use this transformation to find the acceleration.
[tex]\begin{gathered} a=\frac{-24.04(\frac{m}{s})}{4.163\sec } \\ a\approx5.77(\frac{m}{s^2}) \end{gathered}[/tex]Once we have the acceleration, we can use Newton's Second Law to find the net force.
[tex]F=ma[/tex]Let's replace the mass and acceleration to find F.
[tex]\begin{gathered} F=1066\operatorname{kg}\cdot5.77(\frac{m}{s^2}) \\ F=6150.82N \end{gathered}[/tex]Therefore, the net force on the car is 6150.82 Newtons.
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
