Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Kayla was 36 in. tall at age 3. Today, at age 5, she is 42 in. tall.To the nearest percent, what is the percent of change in Kayla'sheight?O A. 2%OB. 8%O C. 14%O D. 17%

Sagot :

What we call percentage is basically this:

We have a number, let's call it 'a' ( a can be 1,2,100,423432, whatever you want!)

Then we divide a by 100 and called the result 1%, in other words:

[tex]\begin{gathered} \frac{a}{100}=1\text{percent} \\ \Rightarrow100(\frac{a}{100})=100percent \end{gathered}[/tex]

This is basically what a percentage is

So, in our problem, a=42in, as this is the final Kayla's height:

Then, we want to know what percentage of 42in is equal to 42in-36in=6in (change in Kayla's height)

[tex]\begin{gathered} x(\frac{42}{100})=6 \\ \Rightarrow x=(\frac{100}{42})\cdot6=14.3\text{ approx} \end{gathered}[/tex]

So, the difference in percentage is: 14.3% which is the option C

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.