Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Kayla was 36 in. tall at age 3. Today, at age 5, she is 42 in. tall.To the nearest percent, what is the percent of change in Kayla'sheight?O A. 2%OB. 8%O C. 14%O D. 17%

Sagot :

What we call percentage is basically this:

We have a number, let's call it 'a' ( a can be 1,2,100,423432, whatever you want!)

Then we divide a by 100 and called the result 1%, in other words:

[tex]\begin{gathered} \frac{a}{100}=1\text{percent} \\ \Rightarrow100(\frac{a}{100})=100percent \end{gathered}[/tex]

This is basically what a percentage is

So, in our problem, a=42in, as this is the final Kayla's height:

Then, we want to know what percentage of 42in is equal to 42in-36in=6in (change in Kayla's height)

[tex]\begin{gathered} x(\frac{42}{100})=6 \\ \Rightarrow x=(\frac{100}{42})\cdot6=14.3\text{ approx} \end{gathered}[/tex]

So, the difference in percentage is: 14.3% which is the option C

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.