Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
The final pressure of the gas inside the ballon is 0.17 atm.
To solve this problem, we would need to use ideal gas equation.
Combined Gas Equation
This is a combination of the three major gas laws which are Boyle's law, Charles law and Pressure Law.
This is given as
[tex]\frac{p_1v_1}{t_1}=\frac{p_2v_2}{t_2}[/tex]we can define our variables
V1 = 1.2L
P1 = 1.1 atm
T1 = 25°C = (25 + 273.15)K = 298.15K
V2 = 6.7L
T2 = 75°C = (75 + 273.15)K = 348.15K
P2 = ?
Let's substitute the values into the equation above and solve for the final pressure
[tex]\begin{gathered} \frac{p_1v_1}{t_1}=\frac{p_2v_2}{t_2} \\ p_2=\frac{p_1v_1t_2}{v_2t_1} \\ p_2=\frac{1.1\times1.2\times348.15}{6.7\times298.15} \\ p_2=0.17\text{atm} \end{gathered}[/tex]The final pressure of the gas inside the ballon is 0.17 atm.
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.