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For a standard-position angle determined by the point (x, y), what are the values of the trigonometric functions?For the point (6, 8), find csc θ and sec θ.

For A Standardposition Angle Determined By The Point X Y What Are The Values Of The Trigonometric FunctionsFor The Point 6 8 Find Csc Θ And Sec Θ class=

Sagot :

Given:

The points is (6,8)

Required:

To find

[tex]csc\theta\text{ and sec}\theta[/tex]

Explanation:

Let a represent length of the opposite side:

[tex]a=8[/tex]

Let b represent the length of the adjacent side:

[tex]b=6[/tex]

The length of the hypotenuse is:

[tex]\begin{gathered} h=\sqrt{a^2+b^2} \\ =\sqrt{8^2+6^2} \\ =\sqrt{64+36} \\ =\sqrt{100} \\ =10 \end{gathered}[/tex]

Now,

[tex]\begin{gathered} csc\theta=\frac{h}{a} \\ =\frac{10}{8} \\ =\frac{5}{4} \end{gathered}[/tex][tex]\begin{gathered} sec\theta=\frac{h}{b} \\ =\frac{10}{6} \\ =\frac{5}{3} \end{gathered}[/tex]

Final Answer:

Option(b) is correct.

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