Answered

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Use the zeros and the labeled point to write the quadratic functionrepresented by the graph.Ay(3,9)10-х-10510-10--20-

Sagot :

Zeros of graph:

[tex]\begin{gathered} x_1=-6 \\ x_2=2 \end{gathered}[/tex]

Vertex: ( -2 , -16 )

Labled point: ( 3, 9 )

To get the quadratic expression:

[tex]y=a(x-h)^2+k[/tex]

Where:

• h = -2

,

• k = -16

,

• x = 3 and y = 6

Then...

[tex]\begin{gathered} 9=a\times(3-(-2))^2+(-16) \\ 9=a\times(5)^2-16 \\ 9=a\times25-16 \\ a=\frac{25}{25}=1 \end{gathered}[/tex]

Standard form:

[tex]y=(x+2)^2-16[/tex]

General form (solving the quadratic expression):

[tex]y=x^2+4x-12[/tex]

Answer: C.

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