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Sagot :
Given:
[tex]y=x^2[/tex]The odered pairs are (-2,4), (0,0) and (2,4).
Required:
We need to graph the given equation.
Explanation:
The given equation is in the form of a parabola equation.
[tex]y=(x-h)^2+k[/tex]where h=0 and k=0.
We know that the vertex of the parabola is (h,k) =(0,0).
The vertex of a parabola is the point at the intersection of the parabola and its line of symmetry
The points (-2,4) and (2,4) lie on the parabola.
Mark the points (-2,4), (0,0), and (2,4) on the graph and join them by the curve.
Final answer:
The graph of the given function:
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