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Hello, I am looking for some assistance with the problem below for graphing.y = 2/3 x

Sagot :

Explanation

given the function

[tex]y=\frac{2}{3}x[/tex]

it is a linear function, because there is only a variable (x) and the exponent is 1

Step 1

to graph the function The first is by plotting points and then drawing a line through the points

so

a) find the points

i) for x= 0

replace and calculate to find x

so

[tex]\begin{gathered} y=\frac{2}{3}x \\ y=\frac{2}{3}(0)=0 \\ so\text{ point 1 \lparen 0,0\rparen} \end{gathered}[/tex]

P1(0,0)

ii) for x=3

[tex]\begin{gathered} y=\frac{2}{3}x \\ y=\frac{2}{3}(3)=2 \\ so\text{ point 2 \lparen3,2\rparen} \end{gathered}[/tex]

Step 2

finally, draw a line that passes trought P1 and P2:

so, the graph would be

I hope this helps you

View image RhandyU34536
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