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Sagot :
ANSWER
B. The average speed is greater than the average velocity.
EXPLANATION
We want to compare the average speed and average velocity of the man.
To find the average speed, we have to divide the distance the man ran by the time he spent running:
[tex]Speed_{\text{avg}}=\frac{Dis\tan ce}{Time}[/tex]He ran 26 miles in 2 hours 14 mins (2.233 hrs). Therefore, his average speed is:
[tex]\begin{gathered} Speed_{\text{avg}}=\frac{26}{2.233} \\ Speed_{avg}=11.64\text{ mi/hr} \end{gathered}[/tex]To find the average velocity, we have to divide the man's displacement (how far he is from his starting point) by the time he spent running:
[tex]Velocity_{\text{avg}}=\frac{Displacement}{Time}[/tex]His displacement from his starting point is 18 miles. Therefore, his average velocity is:
[tex]\begin{gathered} Velocity_{\text{avg}}=\frac{18}{2.233} \\ Velocity_{\text{avg}}=8.06\text{ mi/hr} \end{gathered}[/tex]Therefore, as we can see, the average speed is greater than the average velocity.
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