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Solve the quadratic equation below. Round your answers(s) to the tenths place.(x - 5)(x + 7) = 0The solutions areand

Sagot :

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[tex]\begin{gathered} \mleft(x-5\mright)\mleft(x+7\mright)=0 \\ x(x+7)-5(x+7)=0 \\ x^2+7x-5x-35=0 \\ x^2+2x-35=0 \\ \text{Factorise, we have:} \\ (x-5)(x+7)=0\Rightarrow(x-5)=0,(x+7)=0 \\ x-5=0,x+7=0 \\ x=5,x=-7 \\ \therefore x=5.0\text{ or -7}.0(\text{Tenth Place)} \end{gathered}[/tex]

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