Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A deep sea diving bell is being lowered at a constant rate. After 10 minutes, the bell is at a depth of 400 ft. After 40 minutes the bell is at a depth of 1400 ft. Use the ordered pairs (10, 400) and (40, 1400 to determine the average rate to lower the bell per minute.

Sagot :

Answer:

The average rate to lower the ball per minute is 100/3

Explanation:

Given the ordered pairs (10, 400) and (40, 1400)

The average rate of change is given as:

[tex]\begin{gathered} \frac{y_2-y_1}{x_2-x_1} \\ \\ \text{where} \\ x_1=10 \\ y_1=400 \\ x_2=40 \\ y_2=1400 \end{gathered}[/tex]

Using these parameters, we have:

[tex]\begin{gathered} \frac{1400-400}{40-10} \\ \\ =\frac{1000}{30}=\frac{100}{3} \end{gathered}[/tex]

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.