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A deep sea diving bell is being lowered at a constant rate. After 10 minutes, the bell is at a depth of 400 ft. After 40 minutes the bell is at a depth of 1400 ft. Use the ordered pairs (10, 400) and (40, 1400 to determine the average rate to lower the bell per minute.

Sagot :

Answer:

The average rate to lower the ball per minute is 100/3

Explanation:

Given the ordered pairs (10, 400) and (40, 1400)

The average rate of change is given as:

[tex]\begin{gathered} \frac{y_2-y_1}{x_2-x_1} \\ \\ \text{where} \\ x_1=10 \\ y_1=400 \\ x_2=40 \\ y_2=1400 \end{gathered}[/tex]

Using these parameters, we have:

[tex]\begin{gathered} \frac{1400-400}{40-10} \\ \\ =\frac{1000}{30}=\frac{100}{3} \end{gathered}[/tex]

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