Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To answer this, we have to use the conservation of momentum law, which indicates that the sum of initial momentums is equal to the sum of final momentums after a collision.
[tex]p_{0_1}+p_{0_2}=p_{f_1}+p_{f_2}[/tex]Using the definition of momentum p = mv, we have
[tex]m_1\cdot v_{0_1}+m_2\cdot v_{0_2}=m_1\cdot v_{f_1}+m_2\cdot v_{f_2}[/tex]Replacing the given information, we have
[tex]1\operatorname{kg}\cdot5m/s+3\operatorname{kg}\cdot2m/s=1\operatorname{kg}\cdot4m/s+3\operatorname{kg}\cdot v_{f_2}[/tex]Then, we solve for the final velocity of the heavier car
[tex]\begin{gathered} 5\operatorname{kg}\cdot m/s+6\operatorname{kg}\cdot m/s=4\operatorname{kg}\cdot m/s+3\operatorname{kg}\cdot v_{f_2} \\ 11\operatorname{kg}\cdot m/s-4\operatorname{kg}\cdot m/s=3\operatorname{kg}\cdot v_{f_2} \\ 7\operatorname{kg}\cdot m/s=3\operatorname{kg}\cdot v_{f_2} \\ v_{f_2}=\frac{7\operatorname{kg}\cdot m/s}{3\operatorname{kg}} \\ v_{f_2}\approx2.3m/s \end{gathered}[/tex]Hence, the final speed of the 3.0 kg cart is 2.3 m/s, approximately.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
