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Can you please help me

Sagot :

We will calculate the radius using Pythagoras theorem

[tex]\begin{gathered} \text{hypotenus}^2=opposite^2+adjacent^2 \\ \text{hypotenus}=\text{radisu r} \\ \text{opposite}=6\operatorname{cm} \\ \text{adjacent}=4\operatorname{cm} \end{gathered}[/tex]

By substitution we will have

[tex]\begin{gathered} r^2=6^2+4^2 \\ r^2=36+16 \\ r^2=52 \\ r=\sqrt[]{52\text{ cm}} \end{gathered}[/tex]

Let CF=x, To calculate CF, WE WILL UE THE PYTHAGORAS THEOREM ALSO

[tex]\begin{gathered} \text{hypotenus}^2=opposite^2+adjacent^2 \\ \text{Hypotenus}=\sqrt[]{52\operatorname{cm}} \\ \text{opposite}=x \\ \text{adjacent}=4\operatorname{cm} \end{gathered}[/tex]

By substitution we will have that,

[tex]\begin{gathered} (\sqrt[]{52)^2}=x^2+4^2 \\ 52=x^2+16 \\ x^2=52-16 \\ x^2=36 \\ x=\sqrt[]{36} \\ x=6\operatorname{cm} \end{gathered}[/tex]

Hence,

CF=6cm

The right answer is OPTION A

View image ReagannM681069
View image ReagannM681069