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Sagot :
To solve this question we will make a system of equations and solve them
Since there are 80 coins dimes and nickels
Assume that the number of dimes is d and the number of nickels is n
d + n = 80 (1)
Since the value of the coin is $6.60
Since 1 dollar = 100 cents
The value of the coins = 6.60 * 100 = 660 cents
1 dime = 10 cents
1 nickel = 5 cents
10d + 5n = 660 (2)
Now we will solve the two equations to find n and d
Multiply (1) by -5 to eliminate n
-5(d) + -5(n) = -5(80)
-5d - 5n = -400 (3)
Add (2) and (3)
(10d + -5d) + (5n + -5n) = (660 + - 400)
5d + 0 = 260
5d = 260
Divide both sides by 5 to find d
5d/5 = 260/5
d = 52
Substitute the value of d in (1)
52 + n = 80
Subtract 52 from both sides
52 - 52 + n = 80 - 52
n = 28
There are 28 nickels and 52 dimes
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