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What is the probability of meeting at least one person with the flu in twelve random encounters on campus when the infection rate is 8%

Sagot :

Solution:

[tex]p(x)=(0.08)^x(0.92)^{12-x}[/tex]

The probability of at least one person is;

[tex]\begin{gathered} 1-p(0)=1-(0.08)^0(0.92)^{12-0} \\ \\ =0.6323 \end{gathered}[/tex]

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