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if you cross two heterozygous pea plants, how much offspring needs to be a homozygous dominant

Sagot :

To answer this question we need to do a punnet square of an heterozygous cross, which is as follows:

P: Aa x Aa

Punnet square

[tex]\begin{bmatrix}{\placeholder{⬚}} & {A} & {a} \\ {A} & {AA} & {Aa} \\ {a} & {Aa} & {aa}\end{bmatrix}[/tex]

As we can see we have 25% homozygous dominant, 25% homozygous recessive and 50% heterozygous, therefore the proportion of dominant homozygous is 25%

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