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Sagot :
Given:
[tex]\tan \theta<0\text{ and }\sin \theta>0[/tex][tex]\text{ we know that }\tan \theta=\frac{\sin \theta}{\cos \theta}\text{.}[/tex][tex]\text{ Replace tan}\theta=\frac{\sin \theta}{\cos \theta}\text{ in tan}\theta<0\text{ as follows.}[/tex][tex]\frac{\sin \theta}{\cos \theta}<0[/tex][tex]\text{Multiply cos}\theta\text{ on both sides.}[/tex][tex]\frac{\sin\theta}{\cos\theta}\times\cos \theta<0\times\cos \theta[/tex][tex]\sin \theta<0[/tex][tex]\text{But given that sin}\theta>0[/tex]hence sine value should be equal to 0.
[tex]\sin \theta=0[/tex][tex]\theta=\sin ^{-1}0[/tex][tex]\theta=\sin ^{-1}\sin (n\pi)[/tex][tex]\theta=n\pi\text{ where n is integer.}[/tex]
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