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the sum of three consecutive numbers is one hundred five.What is the smallest of the three numbers

Sagot :

For this problem we know that the sum of 3 consecutive numbers is one hundred five. Let's assume that the 3 numbers is: a, a+1, a+2

And we can set up the following equation:

[tex]a+(a+1)+(a+2)=105[/tex]

And we can solve for a like this:

[tex]3a+3=105[/tex]

We can subtract 3 in both sides and we got:

[tex]3a=102[/tex]

And we can divide both sides by 3 and we got:

[tex]a=\frac{102}{3}=34[/tex]

And we can conclude that the smallest number is 34

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