Answered

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Suppose that a is an angle with seca alpha = - 11/10 and a is not in the third quadrant. Compute the exact value of sina. You do not have to rationalize the denominatorSin a =

Sagot :

Answer:[tex]\sin\alpha=0.41628[/tex]

Explanation:

Given that

[tex]sec\text{ }\alpha=-\frac{11}{10}[/tex]

[tex]\alpha=sec^{-1}(-\frac{11}{10})=155.4^o[/tex]

Now

[tex]\sin\alpha=\sin155.4=0.41628[/tex]

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