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Write the equation of the line that it is perpendicular to [tex]y = 7x - 3[/tex]and passes through the origin

Sagot :

Answer

The equation of the line is

y = (-x/7)

We can cross multiply and write it in the form of

7y = -x

OR

x + 7y = 0

Explanation

The slope and y-intercept form of the equation of a straight line is given as

y = mx + b

where

y = y-coordinate of a point on the line.

m = slope of the line.

x = x-coordinate of the point on the line whose y-coordinate is y.

b = y-intercept of the line.

The relationship between the slopes of two lines that are perpendicular to each other is

m₁m₂ = -1

m₁ = Slope of line 1

m₂ = Slope of line 2

For the given equation, if we compare its equation with y = mx + b,

y = 7x - 3

y = mx + b

m = 7, b = -3

We can now find the slope of the line we want.

m₁m₂ = -1

m₁ = 7

m₂ = ?

m₁m₂ = -1

(7)m₂ = -1

7m₂ = -1

Divide both sides by 7

(7m₂/7) = (-1/7)

m₂ = (-1/7)

Then we can find the equation of the line we want.

For that line,

m = slope = (-1/7)

b = y-intercept (where the line crosses the y-axis) = 0

This is obtained from the point given that the line passes through the origin, (0, 0)

So, we can write y = mx + b

y = (-1/7)x + 0

y = (-x/7)

We can cross multiply and write it in the form of

7y = -x

OR

x + 7y = 0

Hope this Helps!!!