Answered

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How many terms are in the expansion of the binomial below? (x^3 + 2/x)^8A: 9B: 8C: 11D: 10

Sagot :

Given expression is

[tex](x^3+\frac{2}{x})^8[/tex]

This is of the form

[tex](a+b)^n[/tex][tex]\text{where}a=x^3,\text{ b=}\frac{2}{x}\text{ and n=8}[/tex]

Recall that

[tex]In\text{ the binomial expansion of }(a+b)^n,\text{ there are total n+1 terms.}[/tex]

Here n=8.

[tex]In\text{ the binomial expansion of }(x^3+\frac{2}{x})^8,\text{ there are total 8+1=9 terms.}[/tex]

Hence option A is correct.

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