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O GEOMETRY Perimeter involving rectangles and circles A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 88 m long and 67 m wide. What is the length of a training track running around the field? (Use the value 3.14 for π, and do not round your answer. Be sure to include the correct unit in your answer.) 88 m 1 67 m 1 0 m X m² S m³ 1/5 ?

O GEOMETRY Perimeter Involving Rectangles And Circles A Training Field Is Formed By Joining A Rectangle And Two Semicircles As Shown Below The Rectangle Is 88 M class=

Sagot :

[tex]386.38\text{m}[/tex]

Explanation

Step 1

to know the full distance for the track running we need to add twilce the length of the rectangle to the perimeter of the circel, so

so

a) find the circumference of the circle , it is given by

[tex]\begin{gathered} C=\text{ }\pi d\text{ } \\ where\text{ d is the diameter} \end{gathered}[/tex]

hence

[tex]\begin{gathered} let\text{ d=67 m} \\ so \\ C=\pi *67\text{ m=210.38 m} \end{gathered}[/tex]

finally, add twice the length of the rectangle, so

[tex]\begin{gathered} traininin\text{ track = 210.38+\lparen2*88\rparen=210.38+176} \\ traininin\text{ track = 386.38} \end{gathered}[/tex]

therefore, the answer is

[tex]386.38\text{ m}[/tex]

I hope this helps you

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