Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

[tex]( - 4x + 2y \leqslant 4 )(x + 4y \ \textgreater \ - 10)[/tex]how do I graph this

Sagot :

Given the system of inequalities

[tex]\begin{gathered} -4x+2y\leq4 \\ x+4y>-10 \end{gathered}[/tex]

We start by getting the plot of one of these inequalities. Let's start on -4x + 2y ≤ 4. This equation can be rewritten as

[tex]\begin{gathered} 2y\leq4+4x \\ y\leq2+2x \end{gathered}[/tex]

Initially, we consider the equation

[tex]y=2+2x[/tex]

Plotting the equation, we have

Considering the values of these function at

[tex]y\leq2+2x[/tex]

Let's use the same steps implemented above for the second inequality. We have

[tex]\begin{gathered} 4y>-10+x \\ y>\frac{x-10}{4} \end{gathered}[/tex]

Plotting this we have,

The dashed line represents the values that are not included in the equation, as a present for inequalities with less than or greater than. The shaded region represents the solution

After plotting the two inequalities individually, we now superimpose the two graphs. We get

where the darker region represents the solution of the inequalities.

View image VidyaG726655
View image VidyaG726655
View image VidyaG726655
View image VidyaG726655
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.