Answered

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47) The moment of inertia of a 0.98-kg bicycle wheel rotating about its center is 0.13 kg · m2. What is the radius of this wheel, assuming the weight of the spokes can be ignored?

Sagot :

Answer:

0.36 m

Explanation:

The moment of inertial of a wheel can be calculated as

[tex]I=mr^2[/tex]

Where r is the radius of the wheel and m is its mass.

Solving the equation for r, we get

[tex]r=\sqrt[]{\frac{I}{m}}[/tex]

So, replacing I by 0.13 kg m2 and m by 0.98 kg, we get

[tex]r=\sqrt[]{\frac{0.13\operatorname{kg}\cdot m^2}{0.98\operatorname{kg}}}=0.36\text{ m}[/tex]

Therefore, the radius of the wheel is 0.36 m

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