Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Predict the formula for each ionic compoundbarium sulfate:lithium nitrate :cesium sulfide:

Predict The Formula For Each Ionic Compoundbarium Sulfatelithium Nitrate Cesium Sulfide class=

Sagot :

INFORMATION:

We have the following ionic compounds:

- barium sulfate

- lithium nitrate

- cesium sulfide

And we must write their formulas

STEP BY STEP EXPLANATION:

1. Barium sulfate:

To write its formula, we need to use that:

- the element symbol for Barium is Ba, and it has a charge of 2+

- in the given table, sulfate is a polyatomic ion represented by SO4, and it has a charge of 2-

Now, we must add up the charges to verify if the ionic compound is neutral

[tex]2^++2^-=0[/tex]

Since the compound has a net charge of zero, we can write its formula as

[tex]BaSO_4[/tex]

2. Lithium nitrate:

To write its formula, we need to use that:

- the element symbol for Lithium is Li, and it has a charge of 1+

- in the given table, nitrate is a polyatomic ion represented by NO3, and it has a charge of 1-

Now, we must add up the charges to verify if the ionic compound is neutral

[tex]1^++1^-=0[/tex]

Since the compound has a net charge of zero, we can write its formula as

[tex]LiNO_3[/tex]

3. Cesium sulfide:

To write its formula, we need to use that:

- the element symbol for Cesium is Cs, and it has a charge of 1+

- the element symbol for sulfide is S, and it has a charge of 2-

Now, we must add up the charges to verify if the ionic compound is neutral

[tex]1^++2^-=1^-[/tex]

Since the compound has a net different from zero, we need to analyze the compound.

So, if we have just one atom of Cs, the charge would be 1+, but if we take two atoms the charge would be 2(1+) = 2+

Now, verifying the net charge

[tex]2^++2^-=0[/tex]

Now, we can write its formula as

[tex]Cs_2S[/tex]

ANSWER:

barium sulfate:

[tex]BaSO_4[/tex]

lithium nitrate :

[tex]LiNO_3[/tex]

cesium sulfide:

[tex]Cs_2S[/tex]

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.