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Find the slope of the secant line for the g(x) = -20 SQRT x between x = 2 and x = 3

Find The Slope Of The Secant Line For The Gx 20 SQRT X Between X 2 And X 3 class=

Sagot :

Given:

Equation of line is,

[tex]g(x)=-20\sqrt[]{x}[/tex]

The slope of the secant line between x =a and x= b is calculated as,

[tex]\begin{gathered} m=\frac{f(b)-f(a)}{b-a} \\ m=\frac{f(3)-f(2)}{3-2} \\ m=\frac{-20\sqrt[]{3}-(-20\sqrt[]{2})}{1} \\ m=-20\sqrt[]{3}+20\sqrt[]{2} \\ m=20(\sqrt[]{2}-\sqrt[]{3}) \\ m=-6.36 \end{gathered}[/tex]

Answer: slope of the secant line is m = -6.36

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