Answered

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Find the slope of the tangent to thefunction f(x) = 2x4 + 6x² +4 at x = -1

Sagot :

Answer:

-20

Explanations:

Given the function f(x) = 2x^4 + 6x^2 + 4 at x = 1, the slope of the tangent of the function is expressed as:

[tex]f^{\prime}(x)=8x^3+12x[/tex]

Substitute the value of x = -1 into the fucntion

[tex]\begin{gathered} f^{\prime}(-1)=8(-1)^3+12(-1) \\ f^{\prime}(-1)=8(-1)-12 \\ f^{\prime}(-1)=-8-12 \\ f^{\prime}(-1)=-20 \end{gathered}[/tex]

Hence the slope of the tangent to the function at x = -1 is -20

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