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Sagot :
Let's begin by listing out the information given to us:
Initial fee = $5
Fee per stop = $2.75
Amount with Julia = $21
What is the highest number of stops she can make?
S = the number of stops Julia bought
Julia pays the initial fee of $5. We subtract this from the $21, we have
$ (21 - 5) = $16
Julia has $16 left to buy her stops. She cannot spend beyond the amount of money with her (altogether $21). She spends lesser than or equal to $21 (≤ $21)
The inequality that describes this scenario is given by:
initial fee + fee per stop * number of stops ≤ 21
5 + 2.75 * S ≤ 21
Hence, option A is the correct answer
What is the largest number of stops that Julia can afford?
This is gotten by dividing the amount left after subtracting the initial fee by the fee per stop
n = 16/2.75 = 5.82 = 5 stops (rounding downwards)
We round downwards because the number of stops must be a whole number and it must be lesser than or equal to $21 altogether
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