Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

I need help graphing and I need to know the coordinates. The graph goes up to 12.

I Need Help Graphing And I Need To Know The Coordinates The Graph Goes Up To 12 class=

Sagot :

We have the next given function:

[tex]f(x)=\sqrt[3]{x}-2[/tex]

To find the first point, we need to use:

[tex]\sqrt[3]{x}=0[/tex]

Solve the equation for x:

[tex](\sqrt[3]{x})^3=(0)^3[/tex][tex]x=0[/tex]

So, when x=0, we got the first point (0, -2), because:

[tex]y=\sqrt[3]{x}-2[/tex][tex]y=0-2[/tex]

Then

[tex]y=-2[/tex]

Let's find the points on right, let use x=8 and x=27

Replace on the function, when x=8

[tex]y=\sqrt[3]{x}-2[/tex][tex]y=\sqrt[3]{8}-2[/tex][tex]y=2-2[/tex][tex]y=0[/tex]

So, it represents the point (8,0)

Now, when x=27

[tex]y=\sqrt[2]{27}-2[/tex][tex]y=3-2[/tex][tex]y=1[/tex]

This corresponds to the point (27,1)

Now, for points on the left side:

When x=-8

[tex]y=\sqrt[3]{-8}-2[/tex][tex]y=-2-2=-4[/tex]

Which represents the point (-8,-4)

When x=-27

[tex]y=\sqrt[3]{-27}-2[/tex][tex]y=-3-20-5[/tex]

Which represents the point (-27, -5)

Finally, graph these four points on the cartesian plane.

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.